Most threads asking about this seem to end up with the advice "you can buy Sulfuric acid at the auto store" being repeated several times, but I'm asking a very specific question and thus the former is not going to be a helpful answer
We know we can substitute Sodium bisulfate for Sulfuric acid (in, for example, silver bleaches), but I've been hard pressed to find a verified w/v formula for doing so.
I'm sure if I understood moles and whatnot I could work it out myself, but as I don't, I can't ... hence the question.
After a bit of digging around I found this post in this thread .
In that post, it is suggested that 4.3g of anhydrous bisulfate (or ~5g monohydrate) is equivalent to 1ml of concentrated Sulfuric acid.
From that, I have inferred that if I want 1000ml equivalent of (say) a 10% solution of Sulfuric acid in water, then I would require 430g of Sodium bisulfate dissolved in 1000ml of water (or 500g in 1000ml if the bisulfate is in monohydrate form).
(This is "for all practical purposes" rather than scientific exactitude)
If this post catches the eye of one of our resident chemists, could they confirm (or correct) the substitution ratio(s)?
thanks in advance