wait wait wait. Are they strobes or are they continuous lights? The power is measured quite differently in the two cases.

Continuous light (actually, the electrical power into the light) is measured in watts (which is joules per second, i.e. rate of energy flow), whereas power of strobes (being instantaneous) is measured in watt-seconds, i.e. joules. So with a strobe, 200W-s means 200J, which is the total energy going into a single pulse. If you were using a 200W continuous light with the same efficiency as the strobe, it would take 1s of illumination to get the same amount of light. Say you had a 400W-s strobe, it would take 2s for the 200W continuous light to produce the same illumination*.

The next issue is efficiency. If they're continuous lights, the efficiency varies hugely between technologies: tungsten, HID/CMH, fluorescent. You get more light from a 150W fluorescent than from a 500W tungsten, so just quoting the electrical power consumption is not sufficient unless you know what sort of light is involved. The technologies also differ in their colour temperature (orange/blue ratio) as well as their colour quality (CRI), i.e. ability to accurately render different hues.

Oh how I wish light vendors would start selling their lights with luminous-flux numbers as the primary measurement!

Edit: to answer the question... it depends. If they're continuous lights and you have stationary subjects (not people), you can just expose as long as necessary. If they're people, 200W fluorescents are probably fine as long as you're not expecting to shoot at f/16 1/250. If they're strobes, 200Ws is enough to get about f/16-f/22 from a small (60x60cm) softbox at a metre, so good enough for single-person portraits probably, depending on how you like to shoot and how big/slow your film is.

*
Power(W) = Energy(J) / Time(s)
Energy(J) = Power(W) * Time(s)
hence people quoting strobe energy in "watt-seconds". A physicist would slap you if he heard such a term.

Given that a strobe's duration is typically about 1ms and say it had 400J=400W-s of energy, the power from the flash is actually 400/0.001 = 400 kilowatts. But the energy is still only 400J, and it's the total energy hitting the film that matters, not (ignoring reciprocity-failure issues) not how fast it hits the film.