OK basically he say a normal scene has a contrast of 2,10 right. He uses a log of 1,05 for paper. His equation is G= DR/SBR, so G=1,05/2,10 which equals 0,5.
OK basically he say a normal scene has a contrast of 2,10 right. He uses a log of 1,05 for paper. His equation is G= DR/SBR, so G=1,05/2,10 which equals 0,5.