• Originally Posted by Alan Johnson
By my calculation your formula is:
Borax .................................................. 18g
Ascorbic Acid..........................................6g
p-aminophenol as sodium aminophenolate.....1.04g
Sodium Hydroxide.....................................0.96 g
Sodium Sulfite..........................................4 g
Water to................................................ .1L
I think that this formula can be rewrited in more simple form. 1st step:

C6H8O6 + NaOH = C6H7O6Na + H2O

0.96g NaOH + 4.23g Ascorbic acid = 4.76g Sodium ascorbate

leave 6g-4.23g=1.77g Ascorbic Acid. 2nd step:

2C6H8O6 + Na2B4O7 + 5H2O = 2C6H7NaO6 + 2H3BO3

1.77g Ascorbic acid + 1.91g Borax = 2g Sodium ascorbate + 0.62g Boric acid

rest 18g-1.91g=16.1g Borax. so formula will be next:

Sodium Sulfite........................................... 4g
Sodium p-aminophenolate .......................1.04g
Sodium ascorbate ...................................6.8g
Borax .................................................. 16.1g
(Boric acid ..............................................0.62 g)*
Water to................................................ .1L

I think that boric acid can be omitted, because ratio borax-boric acid is 1:25.