Noah,
Note that JohnnyWalker was correct and that his method is equivalent. In his example, TO = 20sec, LO = 4in, LN = 8in therefore TN = 20*2^2 or 80 seconds, which is 4 times the original time. This is, of course, because (LN/LO)^2 = LN^2/LO^2.
Noah,
Note that JohnnyWalker was correct and that his method is equivalent. In his example, TO = 20sec, LO = 4in, LN = 8in therefore TN = 20*2^2 or 80 seconds, which is 4 times the original time. This is, of course, because (LN/LO)^2 = LN^2/LO^2.