</span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Aggie @ Feb 12 2003, 08:25 PM)</td></tr><tr><td id='QUOTE'>could you put that in blonde speak?</td></tr></table><span class='postcolor'>

Although it will take a while until I reach your level of an "Advanced Member", I nevertheless will give it a try ;-)

If your lab-meter shows a reading of 1 second for the shadows and a reading of 8 Seconds for the highlights, the density range (contrast) of your negative is 8:1. However, Photo Technicians do not calculate with arithmetic ratios, but use logarithms instead. The density range of your negative would be stated as log(8) = 0.9logD. In this case, a paper with an ISOR value of 0,9 x 100 = 90 would have exactly the right gradation. Such a paper would map the shadows of your negative to black and the highlights to white and thus gives you the best separation of in-between densities (i.e. the broadest range of tonal values).